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1. Three boys have marbles in the ratio of 19: 5: 3 If the boy with the least number has 9 marbles, how many marbles does the boy with the greatest number have?
- A. 57
- B. 57
- C. 57
- D. 57
Answer: Option A
Explanation:
Let's call the number of marbles each boy has as follows:
Boy A has 19x marbles. Boy B has 5x marbles. Boy C has 3x marbles.
We are given that Boy C has the least number of marbles, which is 9. So, we can set up the equation:
3x = 9
Now, let's solve for x:
3x = 9 x = 9 / 3 x = 3
Now that we know the value of x, we can find the number of marbles Boy A has:
Boy A has 19x = 19 * 3 = 57 marbles.
So, the boy with the greatest number of marbles is Boy A, and he has 57 marbles.
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