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1. The difference of two numbers is 11 and one-fifth of their sum is 9. Find the numbers.
- A. 28 and 16
- B. 28 and 16
- C. 28 and 16
- D. 28 and 16
Answer: Option B
Explanation:
Let's call the two numbers x and y. We're given two pieces of information:
The difference between the two numbers is 11: x - y = 11.
One-fifth of their sum is 9: (1/5)(x + y) = 9.
We can start by solving the first equation for one of the variables and then substitute it into the second equation:
From the first equation, we can express y in terms of x: y = x - 11.
Now, substitute this expression for y into the second equation:
(1/5)(x + x - 11) = 9
Now, simplify and solve for x:
(1/5)(2x - 11) = 9
Multiply both sides by 5 to get rid of the fraction:
2x - 11 = 45
Add 11 to both sides:
2x = 45 + 11 2x = 56
Now, divide by 2:
x = 56 / 2 x = 28
Now that we have found x, we can find y using the first equation:
y = x - 11 y = 28 - 11 y = 17
So, the two numbers are 28 and 17.
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