Discuss Forum
1. City B is 8 miles east of City A. City C is 6 miles north of City B. City D is 16 miles east of City C and City E is 12 miles north of City D. What is the distance from City A to City E?
- A. 10 miles
- B. 10 miles
- C. 10 miles
- D. 10 miles
Answer: Option D
Explanation:
By law of Right angle triangle,
we can find oiut the distance of AC and CE. Thus, the entire distance from A to E.
Now,
AC = √(AB2 + CB2) = √(82 + 62) = √(64 + 36) = √(100) = 10
Again, CE = √(CD2 + DE2) = √(162 + 122) = √( 256 + 144) = √(400) = 20
Thus,
AE = AC + CE = 10 + 20 = 30 miles
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