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1. A beg contains 2 red, 3 green and 2 blue balls. If two balls are drawn at random, what is the probability that none of the balls drawn is blue ?
- A. 10/21
- B. 10/21
- C. 10/21
- D. 10/21
Answer: Option A
Explanation:
n(S) = 7C2 = 21
n( E) = 5C2 = 5! /2! 3! = 10
কোনো বলই নীল না হওয়ার সম্ভাবনা = n( E) / n(S) = 10/21
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