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1. A shopkeeper combined X liters of a solution containing 10% of certain material Q, with 10 liters of another solution that contained 2% of that materiale Q, to produce Z liters of a solution that had 5% of Q. What is the value of X?
- A. 5 liters
- B. 5 liters
- C. 5 liters
- D. 5 liters
Answer: Option B
Explanation:
Hints:
x লিটার Q উপাদান আছে = x এর 10/100 = x/10
10 লিটার Q উপাদান আছে = 10এর 2/100 = 1/5
Z লিটারে Q উপাদান আছে = ( x + 10) এর 5/100 = (x + 10)/20
শর্তমতে, x/10 + 1/5 = (x + 10) / 20
10x + 20 = 5x + 50
10x - 5x = 50 - 20
5x = 30
x = 6
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