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1. The smallest 5-digit number exactly divisible by 41 is :
- A. 10004
- B. 10004
- C. 10004
- D. 10004
Answer: Option A
Explanation:
Hints: The smallest 5 digit number = 10000
এটা কে 41 দ্বারা ভাগ করলে ভাগশেষ থাকে 37
এখন, Required number = 10000 + (41 - 37) = 10004
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