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1. The smallest 5-digit number exactly divisible by 41 is :

  • A. 10004
  • B. 10004
  • C. 10004
  • D. 10004

Answer: Option A

Explanation:

Hints: The smallest 5 digit number = 10000

এটা কে 41 দ্বারা ভাগ করলে ভাগশেষ থাকে 37

এখন, Required number = 10000 + (41 - 37) = 10004


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