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1. The present ages of three persons are in the ratio of 4: 7:9 Eight years ago, the sum of their ages was 56. what are their present ages in years?
- A. 8, 20, 28
- B. 8, 20, 28
- C. 8, 20, 28
- D. 8, 20, 28
Answer: Option B
Explanation:
Let, their present ages be, 4x, 7x, 9x respectively
Then, ( 4x - 8) + ( 7x - 8) + ( 9x - 8) = 56
20x = 80
x = 4
Present ages are 4x = 16, 7x = 28 and 9x = 36 years
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