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1. x2- x - 12 = 0 সমীকরণের মূলদ্বয় নিচের কোনটি?
- A. 3,-4
- B. 3,-4
- C. 3,-4
- D. 3,-4
Answer: Option B
Explanation:
x²−x−12 = 0
= > x²−4x + 3x−12 = 0
= > x(x−4) + 3(x−4) = 0
= >⟹(x + 3)(x−4) = 0
x + 3 = 0
∴⟹x = −3 or
x - 4 = 0
∴ x = 4
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