BD Merit - Freelancing, BCS, Bank, Primary, Admission, NTRCA

Discuss Forum

1. $\frac{\sqrt{2}}{\sqrt{6} + 2} =$

A. $\sqrt{3} + \sqrt{2}$
B. $\sqrt{3} + \sqrt{2}$
C. $\sqrt{3} + \sqrt{2}$
D. $\sqrt{3} + \sqrt{2}$

Answer: Option C

Explanation:

Post your comments here:

Name:

Mobile:

Email:(Optional)

» Your comments will be displayed only after manual approval.