Let's assume Frank scored "x" three-point baskets and "y" two-point baskets. We are given that Frank scored 26 points, and all of his points came from two-point or three-point baskets. We also know that he scored at least one three-point basket. So, we have the following equations: 3x (for the three-point baskets) + 2y (for the two-point baskets) = 26 (total points) x ≥ 1 (at least one three-point basket) We want to find the maximum number of two-point baskets (y) Frank could have scored. To do this, we'll try to maximize "y" while satisfying the given conditions. Let's start by substituting the minimum value for "x" (which is 1) into equation 1: 3(1) + 2y = 26 3 + 2y = 26 Now, subtract 3 from both sides: 2y = 26 - 3 2y = 23 Divide by 2: y = 23 / 2 y = 11.5 Since the number of baskets must be a whole number (you can't have half a basket), we'll round down to the nearest whole number: y = 11 So, Frank could have scored a maximum of 11 two-point baskets.