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1. a chemial is mixed 30 ml mixed , 10 ml is acid , how much ml of acid must be mixed such that a 50/50 mixure of water and acid is attend if no additional water is added
- A. 20
- B. 20
- C. 20
- D. 20
Answer: Option B
Explanation:
To achieve a 50/50 mixture of water and acid, you need to add an equal amount of water to the existing 10 ml of acid. Since you have 30 ml of the mixture, which already contains 10 ml of acid, you need to add an additional 10 ml of water (equal to the amount of acid) to balance it out. So, the answer is 10 ml.
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