Discuss Forum
1. The sum of the ages of the father and son is 80 years. If ten years ago the age of father was three times that of his son, find the present age of the son
- A. 55
- B. 55
- C. 55
- D. 55
Answer: Option B
Explanation:
Let,
Son = x years
Then, Father = (80-x) years
10 years ago,
Son was = (x-10) years
Father was = (80-x-10) = (70-x) years
ATQ,
70-x = 3(x-10)
=> 70-x = 3x-30
=> 4x = 100
=> x = 100÷4 = 25 years
So, Son is 25 years old.
Ans. 25
Post your comments here: