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1. $a + b + c = 0$

Answer: Option D

Explanation:

we have (a^{3} + b^{3} + c^{3} - 3 abc) = (a + b + c) \times (a^{2} + b^{2} + c^{2} - ab - bc - ac) when a + b + c = 0 [given] then, a^{3} + b^{3} + c^{3} = 3 abc \Rightarrow \frac{a^{3}}{abc} + \frac{b^{3}}{abc} + \frac{c^{3}}{abc} = 3 \Rightarrow \frac{a^{2}}{bc} + \frac{b^{2}}{ac} + \frac{c^{2}}{ab} = 3

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