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1. If 3 sides of a triangle are 6 cm, 8 cm, and 10 cm, then the altitude of the triangle, using the largest side as its base, will be-

Answer: Option A

Explanation:

a = 6 cm, b = 8 cm, c = 10 cm So, s = \frac{a + b + c}{2} = \frac{6 + 8 + 10}{2} = \frac{24}{2} = 2 area of triangle = \frac{1}{2} \times base \times height = \sqrt{s (s - a) (s - b) (s - c)} or, \frac{1}{2} \times base \times height = \sqrt{12 (12 - 6) (12 - 8) (12 - 10)} or, \frac{1}{2} \times base \times height = \sqrt{12 \times 6 \times 8 \times 2} or, \frac{1}{2} \times base \times height = \sqrt{576} or, \frac{1}{2} \times 10 \times height = 24 or, height = \frac{48}{10} = 4.8 cm

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