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1. $\frac{1}{\sqrt{2}}, 1, \sqrt{2} . . .$

Answer: Option A

Explanation:

প্রথম পদ a = \frac{1}{\sqrt{2}} সাধারণ অনুপাত r = \frac{1}{\frac{1}{\sqrt{2}}} = \sqrt{2} ধরি n তম পদ হবে 8 \sqrt{2} .' . {ar}^{n - 1} = 8 \sqrt{2} \Rightarrow \frac{1}{\sqrt{2}} {(\sqrt{2})}^{n - 1} = {(\sqrt{2})}^{6} . \sqrt{2} \Rightarrow {(\sqrt{2})}^{n - 2} = {(\sqrt{2})}^{7} \Rightarrow n - 2 = 7 .' . n = 9

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