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1. $x^{2} - y^{2}, x^{3} - y^{3}, x^{4} + x^{2} y^{2} + y^{4}$

Answer: Option D

Explanation:

{১ম রাশি= x}^{2} {-y}^{2} = (x + y) (x - y) {২য় রাশি= x}^{3} {-y}^{3} = (x - y) (x^{2} + x y + y^{2}) {৩য় রাশি= x}^{4} {+x}^{2} y^{2} {+y}^{4} = {(x^{2})}^{2} {+2x}^{2} y^{2} + {(y^{2})}^{2} {-x}^{2} y^{2} = {(x^{2} + y^{2})}^{2} - {(xy)}^{2} = (x^{2} + y^{2} + x y) (x^{2} + y^{2} - x y) 1 ব্যাতীত কোনো সধারন উৎপাদক নেই। অতএব গ.সা.গু=1

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