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1. $x + 2^{\frac{1}{3}} + 2^{\frac{2}{3}} = 0$

Answer: Option B

Explanation:

x + 2^{\frac{1}{3}} + 2^{\frac{2}{3}} = 0 b a, x = - (2^{\frac{1}{3}} + 2^{\frac{2}{3}}) b a, x^{3} = - \{{(2^{\frac{1}{3}} + 2^{\frac{2}{3}})}^{3}\} b a, x^{3} = - \{{(2^{\frac{1}{3}})}^{3} + {(2^{\frac{2}{3}})}^{3} + 3 . 2^{\frac{1}{3}} . 2^{\frac{2}{3}} . (2^{\frac{1}{3}} + 2^{\frac{2}{3}})\} b a, x^{3} = - \{2 + 4 + 3.2 . (- x)\} b a, x^{3} = - 6 + 6 x b a, x^{3} - 6 = 6 x

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