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1. $\log_{2} 64 + \log_{2} 8$

Answer: Option A

Explanation:

{\log_{2}}^{64} + {\log_{2}}^{8} = {\log_{2}}^{2^{6}} + {\log_{2}}^{2^{3}} = 6 \times 1 + 3 \times 1 = 6 + 3 = 9

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