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1. $\log_{x} \frac{1}{9} = - 2$

Answer: Option A

Explanation:

দেওয়া আছে, \log_{x} (\frac{1}{9}) =-2 \Rightarrow x^{- 2} = \frac{1}{9} \Rightarrow \frac{1}{x^{2}} = \frac{1}{3^{2}} \Rightarrow x^{2} = 3^{2} ∴ x = \pm 3 কিন্তু লগারিদম ভিত্তি (B a s e) ঋণাত্মক হতে পারে না বলে x=-3 গ্রহণযোগ্য নয়। ∴ x = 3

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