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1. $x^{2} + y^{2} + z^{2} = 2, x + y + z = 2$

Answer: Option C

Explanation:

{(x + y + z)}^{2} = (x^{2} + y^{2} + z^{2}) + 2 (x y + y z + z x) = 2 (x y + y z + z x) = {(x + y + z)}^{2} - (x^{2} + y^{2} + z^{2}) = 2^{2} - 2 = 2

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