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1. ${(\sqrt{2})}^{8} \times {(\sqrt[3]{2})}^{9}$

Answer: Option B

Explanation:

({\sqrt{2)}}^{8} \times (\sqrt[3]{2})^{9} = 2^{\frac{8}{2}} \times 2^{\frac{9}{3}} = 2^{4} \times 2^{3} = 2^{7} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 128

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