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1. $\frac{3 . 2^{n} - 4 . 2^{n - 2}}{2^{n} - 2^{n + 1}} = ক ত ?$

Answer: Option C

Explanation:

\frac{3 . 2^{n} - 4 . 2^{n - 2}}{2^{n - 2^{n + 1}}} = \frac{3 . 2^{n} - 2^{2} . 2^{n - 2}}{2^{n} - 2^{n} . 2^{1}} = \frac{3 . 2^{n} - 2^{2 + n - 2}}{2^{n} (1 - 2)} = \frac{2^{n} (3 - 2)}{2^{n} . (- 1)} = \frac{2}{- 1} = - 2

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