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1. $i^{- 49}$

A. -1
B. -1
C. -1
D. -1

Answer: Option D

Explanation:

i^{- 49} = \frac{1}{i^{49}} = \frac{1}{i^{48} . i} = \frac{1}{{(i^{4})}^{12} . i} = \frac{1}{{(1)}^{12} . i} = \frac{1}{1 . i} = \frac{- i^{2}}{i} = - i

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