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1. $\frac{\sqrt{২}}{\sqrt{৬} + ২} = কত ?$

Answer: Option D

Explanation:

\frac{\sqrt{২}}{\sqrt{৬} + ২} = \frac{\sqrt{২}}{\sqrt{২} . \sqrt{৩} + \sqrt{২} . \sqrt{২}} = \frac{\sqrt{২}}{\sqrt{২} (\sqrt{৩} + \sqrt{২})} = \frac{\sqrt{৩} - \sqrt{২}}{(\sqrt{৩} - \sqrt{২}) (\sqrt{৩} + \sqrt{২})} = \frac{\sqrt{৩} - \sqrt{২}}{৩ - ১} = \sqrt{৩} - \sqrt{২}

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