BD Merit - Freelancing, BCS, Bank, Primary, Admission, NTRCA

Discuss Forum

1. $a^{2} - b^{2}, a^{3} - b^{3}, a^{4} + a^{2} b^{2} + b^{4}$

Answer: Option A

Explanation:

a^{2} - b^{2} = (a + b) (a - b) a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2}) a^{4} + a^{2} b^{2} + b^{4} = a^{4} + 2 a^{2} b^{2} + b^{4} - a^{2} b^{2} = {(a^{2} + b^{2})}^{2} - {(a b)}^{2} = (a^{2} + a b + b^{2}) (a^{2} - a b + b^{2})

১ম,২য় ও ৩য় রাশির সাধারণ উতপাদক=1 গ.সা.গু=1

Post your comments here:

Name:

Mobile:

Email:(Optional)

» Your comments will be displayed only after manual approval.