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1. $2 \sin θ = \sqrt{3} হলে c o t (n / 2 - θ)$

Answer: Option C

Explanation:

2 \sin θ = \sqrt{3} \Rightarrow \sin θ = \frac{\sqrt{3}}{2} \Rightarrow \sin θ = \sin \frac{π}{3} \Rightarrow θ = \frac{π}{3} c o t (\frac{π}{2} - θ) = \tan θ = \tan \frac{π}{3} = \tan 60 ° = \sqrt{3}

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