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1. $\tan θ = \frac{5}{12}$

Answer: Option D

Explanation:

\Rightarrow (1 - \frac{s i n θ}{c o s θ}) \div (1 + \frac{s i n θ}{c o s θ}) \Rightarrow (1 - t a n θ) \div (1 + \tan θ) \Rightarrow (1 - \frac{5}{12}) \div (1 + \frac{5}{12}) \Rightarrow \frac{12 - 5}{12} \div \frac{12 + 5}{12} \Rightarrow \frac{7}{12} \div \frac{17}{12} \Rightarrow \frac{7}{12} \times \frac{12}{17} \Rightarrow \frac{7}{17}

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