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1. $(\frac{x^{p + q}}{x^{2 r}}) (\frac{x^{q + r}}{x^{2} p}) (\frac{x^{r + p}}{x^{2 q}})$

Answer: Option C

Explanation:

(\frac{x^{p + q}}{x^{2 r}}) (\frac{x^{q + r}}{x^{2 p}}) (\frac{x^{r + p}}{x^{2 q}}) x^{p + q - 2 r} x^{q + r - 2 p} x^{r + p + 2 q} x^{p + q - 2 r + q + r - 2 p + r + p - 2 q} x^{0} = 1

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