Discuss Forum
1.
How many different six-digit numbers can be formed using all of the following digits : 3, 3, 4, 4, 4, 5 ........
- A. 25
- B. 25
- C. 25
- D. 25
Answer: Option D
Explanation:
There are 6 digits among them 2 threes and 3 fours in them total numbers = 6!/(2!x3!) = 60
Post your comments here: