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1.
A train which travels at a uniform speed due to some mechanical fault after traveling for an hour goes at 3/5th of the original speed and reached the destination 2 hours late. If the fault had occurred after traveling another 50 miles, the train would ha
- A. 280
- B. 280
- C. 280
- D. 280
Answer: Option B
Explanation:
Let, the original speed is x and 3/5 th of original speed is 0.6x
50/0.6x - 50/x = 40/60
(250 - 150)/3x = 2/3
100/3x = 2/3
6x = 300
x = 50
3/5 of 50 = 30
speed reduces by = 50 - 30 = 20
It is late by 2 hours and by this time it goes 30*2 = 60
If the train goes with its original speed it took 60/20 = 3 hours after the first hour. That means total 4 hours.
Therefore, total distance covered
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