Discuss Forum
1. The batting average for 40 innings of a cricket player is 50 runs. His highest score in an innings exceeds his lowest score by 172 runs. If these two innings are excluded, the average score of the remaining 38 innings is 48 runs. Find his highest score in
- A. 180 runs
- B. 180 runs
- C. 180 runs
- D. 180 runs
Answer: Option C
Explanation:
Let the lowest score in one innings be x. Then,
Highest score in an innings = x + 172
Total runs in 40 innings = 40 x 50 = 2000
Total runs in 38 innings = 38 x 48 = 1824
Given, 2000 - {x + (x + 172)} = 1824
⇒ 1828 - 2x = 1824 ⇒ 2x = 4 ⇒ x = 2
∴ Highest score = 172 + 2 = 174
Post your comments here: