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1. The sum of 6 consecutive odd numbers exceeds twice the largest by 38. Find the sum of the six numbers?
- A. 57
- B. 57
- C. 57
- D. 57
Answer: Option B
Explanation:
Let x represent the smallest number. Then the other number are
x + 2, x + 4, x + 6, x + 8 and x + 10. x + 10 is the largest.
The sum of these is 6x + (2 + 4 + 6 + 8 + 10) = 6x + 30
We are told that this is 38 greater than twice the largest, so
6x + 30 = 2(x + 10) + 38 = 2x + 58.
or, 4x = 28
∴x = 7
Then the sum is 6×7 + 30 = 72.
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