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1. A student first reduced a number by 20 percent and then increased it again by 20 percent. If the difference between the two new numbers was 8, then what is the original number?
- A. 40
- B. 40
- C. 40
- D. 40
Answer: Option B
Explanation:
Suppose, Total marks = 100
20% reduced = 80
Then, 20% increased = 80 + 80 of 20% = 96
Difference = 100 - 96 = 4
4 difference then orginal number = 100
8 difference then orginal number = (100×8)/4
= 200
20% increased = 96%
Difference between two new number= 96-80 = 16
Difference is 16 when the original number is 100
,, ,, 8 ,, ,, = 50
Answer : 50
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