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1. A mixture of 20 kg of sprit and water contains 10% water. How much water must be added to this mixture to rais the percentage of water to 25%?

  • A. 4
  • B. 4
  • C. 4
  • D. 4

Answer: Option A

Explanation:

Amount of water in the mixture = 10% of 20 kg = 2 kg

So, amount of spirit = 20 - 2 = 18 kg

Percentage of spirit in new mixture = 100 - 25 = 75%

Now, 75% of mixture = 18 kg

So, 100% of mixture = 18 x 100 / 75 = 24 kg

So, amount of water need to be added = 24 - 20 = 4 kg


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