1 . ∫dxe2x+e-2x=

• A. ${\tan }^{-1}\left(e^{2x}\right)+c$
• B. $\frac{1}{2}{\tan }^{-1}\left(e^{2x}\right)+c$
• C. $\frac{1}{2}{\tan }^{-1}\left(e^{-2x}\right)+c$
• D. কোনটিই নয়

Answer: Option B

Explanation: