1 . Rahim average 70 in his first m number of exams. After taking n more exams he had an overall average of 75. In terms of m and n his average for the last n exams was—
- A. 5n/m + 75
- B. (70m + 75n)/(m + n)
- C. 80
- D. (5m + 75)/n
- D. 5m/n + 75
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