BD Merit - Freelancing, BCS, Bank, Primary, Admission, NTRCA

1 . 1x13x3+y3+z3

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Answer: Option D

Explanation:

দেওয়া আছে, x + y + z = 0 . . . . . . . (i) ∴ (\frac{1}{3}) (x^{3} + y^{3} + z^{3}) = \frac{1}{3} (x^{3} + y^{3} + z^{3} - 3 x y z) + x y z = \frac{1}{3} \{(x + y + z) (x^{2} + y^{2} + z^{2} - x y - y z - z x)\} + x y z = \frac{1}{3} \{0 (x^{2} + y^{2} + z^{2} - x y - y z - z x)\} + x y z = 0 + x y z = x y z a n s