1 . Find the total cache size: Multiply the number of blocks by the bits per block: 2^10 blocks x 147 bits = 147 KibiBits. Therefore, for a direct mapped cache with 16KB of data, 4-word blocks, and a 32-bit address, the total bits required would be 147 KibiBits.

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Answer: Option False

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2 . It is not possible to have a deadlock involving only one single process. The deadlock involves a circular “hold-and-wait” condition between two or more processes, so “one” process cannot hold a resource, yet be waiting for another resource that it is holding. So for one process, deadlock can not be possible .  

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Answer: Option False

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