Let L represent the length of the rectangle in inches, and let W represent the width of the rectangle in inches.

According to the problem, the width is 6 inches less than 3 times the length, so we can write this as an equation:

W = 3L - 6

The perimeter of a rectangle is given by the formula:

Perimeter = 2(L + W)

In this case, the perimeter is 104 inches, so we can write:

104 = 2(L + W)

Now, substitute the expression for W from the first equation into the perimeter equation:

104 = 2(L + (3L - 6))

Simplify the equation:

104 = 2(4L - 6)

Now, distribute the 2 on the right side of the equation:

104 = 8L - 12

Add 12 to both sides of the equation to isolate the 8L term:

104 + 12 = 8L

116 = 8L

Now, divide both sides by 8 to find the value of L:

L = 116 / 8 L = 14.5

So, the length of the rectangle is 14.5 inches.

Now, use the first equation to find the width:

W = 3L - 6 W = 3(14.5) - 6 W = 43.5 - 6 W = 37.5

So, the width of the rectangle is 37.5 inches.