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1 . log27+log8-log1000log1.2

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Answer: Option B

Explanation:

\frac{\log \sqrt{27} + \log 8 - \log \sqrt{1000}}{\log 1.2} = \frac{\log \sqrt{3^{3}} + \log 2^{3} - \log \sqrt{{(2 \times 5)}^{3}}}{\log \frac{12}{10}} = \frac{\log 3^{\frac{3}{2}} + \log 2^{3} - \log (2^{\frac{3}{2}} \times 5^{\frac{3}{2}})}{\log \frac{6}{5}} = \frac{\log 3^{\frac{3}{2}} + \log 2^{3} - \log (2^{\frac{3}{2}} \times 5^{\frac{3}{2}})}{\log 6 - \log 5} = \frac{\frac{3}{2} \log 3 + 3 \log 2 - \frac{3}{2} \log 2 - \frac{3}{2} \log 5}{\log (3 \times 2) - \log 5} = \frac{\frac{3}{2} \log 3 + 3 \log 2 - \frac{3}{2} \log 2 - \frac{3}{2} \log 5}{\log 3 + \log 2 - \log 5} = \frac{\frac{3}{2} \log 3 + \frac{3}{2} \log 2 - \frac{3}{2} \log 5}{\log 3 + \log 2 - \log 5} = \frac{\frac{3}{2} (\log 3 + \log 2 - \log 5)}{\log 3 + \log 2 - \log 5} = \frac{3}{2} = 1.5