BD Merit - Freelancing, BCS, Bank, Primary, Admission, NTRCA

1 . tanθ=8

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Answer: Option B

Explanation:

s e c^{2} θ = 1 + \tan^{2} θ = 1 + {(\sqrt{8})}^{2} = 1 + 8 s e c^{2} θ = 9 s o, s e c θ = 3