BD Merit - Freelancing, BCS, Bank, Primary, Admission, NTRCA

1 . x+3x2x-3y22

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Answer: Option C

Explanation:

\{{(x + 3 x)}^{2} {(x - 3 y)}^{2}\} = {[{\{(x + 3 x) (x - 3 y)\}}^{2}]}^{2} = {[{\{{(x)}^{2} - {(3 y)}^{2}\}}^{2}]}^{2} = {[{\{x^{2} - 9 y^{2}\}}^{2}]}^{2} = {\{x^{4} - 18 x^{2} y^{2} + 81 y^{4}\}}^{2} = (x^{4} - 18 x^{2} y^{2} + 81 y^{4}) (x^{4} - 18 x^{2} y^{2} + 81 y^{4}) = x^{8} - 18 x^{2} y^{2} + 81 x^{4} y^{4} - 18 x^{6} y^{2} + 324 x^{4} y^{4} - 1458 x^{2} y^{6} + 81 x^{4} y^{4} - 1458 x^{2} y^{6} + 651 y^{8} = x^{8} - 36 x^{6} y^{2} + 486 x^{4} y^{4} - 2916 x^{2} y^{6} + 66561 y^{8} ∴ {\{{(x + 3 x)}^{2} {(x - 3 y)}^{2}\}}^{2} এর ৫ টি পদ।