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1 . x4-x2+1=0

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Answer: Option D

Explanation:

x4 - x2 + 1 = 0 Or, x2 + 1/x2 = 1 Or, x + 1/x = √3 Now, x3 + 1/ x3 = ( x + 1/x)3 - 3.x.1/x.( x + 1/x) = 3√3 - 3√3 = 0

৪০ তম বিসিএস প্রিলিমিনারি টেস্ট (03-05-2019)

2 . x4-x2+1=0

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Answer: Option B

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১৬ তম শিক্ষক নিবন্ধন পরীক্ষা (স্কুল সমপর্যায়-২) (30-08-2019)

3 . x4-x2+1=0

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Answer: Option C

Explanation:

x^{4} - x^{2} + 1 = 0 \Rightarrow x^{4} + 1 = x^{2} \Rightarrow x^{2} + \frac{1}{x^{2}} = 1 [x^{2} দ্বারা ভাগ করে]

4 . x4-x2+1=0

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Answer: Option D

Explanation:

x^{4} - x^{2} + 1 = 0 o r, x^{2} + \frac{1}{x^{2}} = 1 o r, x + \frac{1}{x} = \sqrt{3} এখন , x^{3} - \frac{1}{x^{3}} = {(x + \frac{1}{x})}^{3} - 3 . x . \frac{1}{x} . (x + \frac{1}{x}) = 3 \sqrt{3} - 3 \sqrt{3} = 0