3016 . The number of stamps in Ziko's collection is 75% of the number in Pallab's collection. If Pallab has 80 more stamps than Ziko, how many stamps do they have altogether?

A. 320
B. 240
C. 560
D. 620
E. None of these

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Answer: Option C

Explanation:

let, pallab has = X stamps

ziko has = 0.75X stamps

pallab has x - 0.75x = 0.25x more stamps than than ziko.

apq,

0.25x = 80

x = 320

pallab has = 320 stamps

ziko has = 320x.75 = 240

together they have = 320 + 240 = 560

3017 . The number of students in each section of a school is 24, After admitting new students, three new sections were started. Now, the total number of sections is 16 and there are 21 students in each section. The number of new students admited is-

A. 24
B. 14
C. 48
D. 114
E. None of these

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Answer: Option A

Explanation:

4 student নিয়ে section = 16 - 3 = 13

13×24 = 312 students

after admitting new students

13 + = 16 section 21 student নিয়ে

16×21 = 336 students

নতুন student = 336 - 312 = 24

দুর্নীতি দমন কমিশনের সহকারী পরিচালক-১২.০৪.২০১৩

A. 18
B. 24
C. 22
D. 25

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Answer: Option D

Explanation:

সমন্বিত ৭ ব্যাংক || সিনিয়র অফিসার-05-11-2021 ||

A. 4
B. 5
C. 6
D. 7

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Answer: Option C

Explanation:

Here,

(2+3+5+x) / 4 = 4

=> 10+x = 16

=> x = 16-10 = 6.

সমন্বিত ৫ ব্যাংক || অফিসার (ক্যাশ) (11-03-2022)

A. 6.5
B. 4
C. 3
D. 3.5

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Answer: Option C

Explanation:

the sum of the 5 quantities is 5 x 6 = 30. The average of three of these 5 quantities is 8. The sum of the remaining two quantities = 30 - 24 = 6. Average of these two quantities = 6/2 = 3.

3021 . The one - third of the complementary angle to 60° is

A. 150°
B. 100°
C. 40°
D. 10°

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Answer: Option D

Explanation:

Complementary angle of 6০0 is (9০ - 6০)  = 3০0⸫ One third of 3০0 =  1/3×3০0 = 1০0

Assistant Director (General) 06.07.18

A. 45%
B. 56%
C. 64%
D. 75%
E. none of them

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Answer: Option C

Explanation:

Let,

last year present = 100

this year projected present = (100 + 25) = 125

this year Actual present = (100 - 20) = 80

so, the percentage = {(80/125)×100}% = 64%

3023 . The orginal Funding to build a housing development was $1.75 billion. The funding was increased to $2. 5 billion By what percentage was the original funding increased.

A. 38%
B. 52%
C. 43%
D. 75%

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Answer: Option C

Explanation:

Original Funding = $1.75 billion

after increased = $2.5 billion

the original funding increased = $2.5 - $1.75 = $0.75

percentage of original funding increased = ($0.75*100)/ $1.75 = .428 = .43 or 43% (Ans)

3024 . The percentage increase in the area of a rectangle , if each of its sides is increased by 20%, is :

A. 40%
B. 42%
C. 44%
D. 46%

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Answer: Option C

Explanation:

Let,

one side of Rectangular is 100 m

The other side of Rectangular is 200 m

So, Present Area is = 100X200=20000 m2

if increase 20% of both side of rectangular.

Then, one side of Rectangular is= 100 +
100
×
20
100
= 120 m

Other side of Rectangular is = 200 +
200
×
20
100
= 240 m

After increasing the Rectangular area is = 120× 240 = 28800 m2

increasing the Rectangular area is = 28800 - 20000 = 8800 m2

So, % of increasing area is =
8800
×
100
20000
= 44%

Ans: 44%.

Bangladesh Bank - Assistant Director - 2016

A. 13.5 inches
B. 37.5 inches
C. 14.5 inches
D. 15 inches

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Answer: Option B

Explanation:

Let L represent the length of the rectangle in inches, and let W represent the width of the rectangle in inches.

According to the problem, the width is 6 inches less than 3 times the length, so we can write this as an equation:

W = 3L - 6

The perimeter of a rectangle is given by the formula:

Perimeter = 2(L + W)

In this case, the perimeter is 104 inches, so we can write:

104 = 2(L + W)

Now, substitute the expression for W from the first equation into the perimeter equation:

104 = 2(L + (3L - 6))

Simplify the equation:

104 = 2(4L - 6)

Now, distribute the 2 on the right side of the equation:

104 = 8L - 12

Add 12 to both sides of the equation to isolate the 8L term:

104 + 12 = 8L

116 = 8L

Now, divide both sides by 8 to find the value of L:

L = 116 / 8 L = 14.5

So, the length of the rectangle is 14.5 inches.

Now, use the first equation to find the width:

W = 3L - 6 W = 3(14.5) - 6 W = 43.5 - 6 W = 37.5

So, the width of the rectangle is 37.5 inches.

সহকারী পরিচালক(AD) -12.11.2021

A. 30m
B. 50m
C. 60m
D. 70m

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Answer: Option D

Explanation:

Here,perimeter of rectangular,2(a+b)=200

Let, length=a

According to question, Breadth=3a/7

Putting the value in above equation,

We get,length a= 70.

বাংলাদেশ ব্যাংক অফিসার ০২ -১২-২০২২

A. 4 cm
B. 6 cm
C. 10 cm
D. 14 cm

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Answer: Option A

Explanation:

2(x + y) = 20

x + y = 10

6 + y = 10

y = 4.

সমন্বিত ৮ ব্যাংক ও ১ টি আর্থিক প্রতিষ্ঠান || সিনিয়র অফিসার (সাধারণ) (20-01-2023)

A. 160
B. 200
C. 220
D. 180

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Answer: Option B

Explanation:

Let, breadth = x

length = 2x

perimeter, 2(2x+x) = 60

3x = 30

x =10

Now, the area = 2x*x = 2*10*10 = 200 (Ans)

বিসিআইসি | সহকারী প্রকৌশলী (কমার্শিয়াল) | 10-12-2021 || 2021

A. 30m
B. 50m
C. 60m
D. 70m

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Answer: Option D

Explanation:

In case of a rectangle,

2(Length + Width) = perimeter

or, 2(Length + 3/7 of Length) = 200

or, 10/7 of Length = 200/2

So, Length = 200/2 x 7/10 = 70 meter

NRBC Bank PLC || Trainee Assistant Officer (TAO) (26-10-2024) || 2024

A. 18cm
B. 24cm
C. 32cm
D. 36cm

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Answer: Option B

Explanation:

Step 1: Find the sides of the first two squares.

The side of a square is equal to its perimeter divided by 4. Therefore, the sides of the first two squares are:

Side of square 1 = 40cm / 4 = 10cm Side of square 2 = 30cm / 4 = 7.5cm

Step 2: Find the areas of the first two squares.

The area of a square is equal to the side of the square squared. Therefore, the areas of the first two squares are:

Area of square 1 = 10cm * 10cm = 100cm² Area of square 2 = 7.5cm * 7.5cm = 56.25cm²

Step 3: Find the difference of the areas of the first two squares.

The difference of the areas of the first two squares is:

Difference of areas = Area of square 1 - Area of square 2 = 100cm² - 56.25cm² = 43.75cm²

Step 4: Find the side of the third square.

The side of the third square is equal to the square root of the difference of the areas of the first two squares. Therefore, the side of the third square is:

Side of square 3 = √43.75cm² = 6.625cm

Step 5: Find the perimeter of the third square.

The perimeter of the third square is equal to the side of the third square multiplied by 4. Therefore, the perimeter of the third square is:

Perimeter of square 3 = 6.625cm * 4 = 26.5cm

Answer: 24cm

সমন্বিত ১০ ব্যাংক ও আর্থিক প্রতিষ্ঠান || সিনিয়র অফিসার (10-11-2023)

3016 . The number of stamps in Ziko's collection is 75% of the number in Pallab's collection. If Pallab has 80 more stamps than Ziko, how many stamps do they have altogether?

3017 . The number of students in each section of a school is 24, After admitting new students, three new sections were started. Now, the total number of sections is 16 and there are 21 students in each section. The number of new students admited is-

3018 . The numbers 11, 12, 14, x-2, x+4,x+ 9, 32, 38, 47 are arranged in ascending order and the median is 24: find x.

3019 . The numbers 2,3,5 and x have an average equal to 4 . What is x?

3020 . The of 5 quantities is 6. The average of 3 of them is 8. What is the average of the remaining two numbers?

3021 . The one - third of the complementary angle to 60° is

3022 . The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this year actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?

3023 . The orginal Funding to build a housing development was $1.75 billion. The funding was increased to $2. 5 billion By what percentage was the original funding increased.

3024 . The percentage increase in the area of a rectangle , if each of its sides is increased by 20%, is :

3025 . The perimeter of a rectangle is 104 inches. The width is 6 inches less than 3 times the length. find the width of the rectangle.

3026 . The perimeter of a rectangle is 200 meters. The breadth is 3/7 part of the length. What is the length?

3027 . The perimeter of a rectangle is 20cm. If the length of the rectangle is 6cm, then its breadth will be.

3028 . The perimeter of a rectangle is 60 meters. If its length is twice its breadth, then its area ( in m2) is:

3029 . The perimeter of rectangle is 200 meter. The breadth is 3/7 part of the length. What is the length?

3030 . The perimeters of two squares are 40cm and 30cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.

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