1546 . ৯১, ১০১, ১১৭ এবং ১২৩ এর মধ্যে মৌলিক সংখ্যা কোনটি?

A. ৯১
B. ১০১
C. ১১৭
D. ১২৩

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Answer: Option B

Explanation:

Option test:

6n ± 1 = 101

6n - 1= 101

6n = 102

n=1026=17n=1026=17

সুতরাং, 101 মৌলিক

১৭ তম বেসরকারি প্রভাষক নিবন্ধন পরীক্ষা (31-12-2022)

A. ৭৮৪
B. ১২৮৫
C. ১২৩৪
D. ২২৮৪

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Answer: Option B

Explanation:

M - 1000

C - 100

L - 50

X - 10

IV - 4

1548 . After decreasing 24% in the price of an article the discounted price becomes $912. Find the actual price of the article?

A. $1400
B. $1300
C. $1200
D. $1100

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Answer: Option C

Explanation:

Let's denote the actual price of the article as "P."

According to the given information, after decreasing 24%, the discounted price becomes $912. We can represent this as an equation:

P - 0.24P = $912

Now, let's solve for P:

0.76P = $912

Divide both sides by 0.76 to find the actual price:

P = $912 / 0.76 P = $1200

So, the actual price of the article is $1200.

বাংলাদেশ সিকিউরিটিজ অ্যান্ড এক্সচেঞ্জ কমিশন(সহকারী পরিচালক) 19-06-2021

A. 2
B. 5
C. 10
D. 65

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Answer: Option D

Explanation:

To find the smallest possible value of k such that 1040k is the square of an integer, we need to factorize 1040 and then find the least value of k that makes the result a perfect square.

First, let's factorize 1040:

1040 = 2^4 * 5 * 13

Now, to make 1040k a perfect square, we need to make the exponents of all prime factors even. So, we need to find the least value of k that will make the exponents of 2, 5, and 13 even.

Exponent of 2: Since it's already raised to the power of 4, we don't need to change it.

Exponent of 5: We need to raise it to an even power. So, k should be multiplied by 5 to make it even.

Exponent of 13: We need to raise it to an even power. So, k should be multiplied by 13 to make it even.

Now, let's consider the exponents of 5 and 13:

Exponent of 5: It's currently 1, so we need to raise it to an even power, which means multiplying by 5 again. So, k should be at least 5.

Exponent of 13: It's currently 1, so we need to raise it to an even power, which means multiplying by 13 again. So, k should be at least 13.

To make sure both exponents are even, we need to take the least common multiple (LCM) of 5 and 13, which is 65.

So, the smallest possible value of k such that 1040k is the square of an integer is k = 65.

বাংলাদেশ সিকিউরিটিজ অ্যান্ড এক্সচেঞ্জ কমিশন(সহকারী পরিচালক) 19-06-2021

A. 21
B. 0.21
C. 0.021
D. 0.0021

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Answer: Option D

Explanation:

পল্লী বিদ্যুতায়ন বোর্ড। এসিস্ট্যান্ট এনফোর্সমেন্ট কোঅডিনেটর। 31-12-2021

A. প্রথম
B. দ্বিতীয়
C. তৃতীয়
D. চতুর্থ

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Answer: Option B

Explanation:

( - , + ) ( + , + )

২য় | ১ম

৩য় | ৪র্থ

( - , - ) ( + , - )

( - 3, 4) বিন্দুটি দ্বিতীয় চতুর্ভাগে অবস্থিত ।

1552 . In a certain town, the ratio of the number of rented residences to the number of owned residences is 7 : 4. Those are the only two kinds of residences in this town. If there are 150 more rented than owned residences in this town, what is the total number of residences in the town?

A. 200
B. 350
C. 550
D. 700

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Answer: Option C

Explanation:

Let R be the number of rented residences and O be the number of owned residences.

According to the given information, we have the ratio of rented to owned residences as 7:4:

R/O = 7/4

We are also given that there are 150 more rented residences than owned residences:

R = O + 150

Now, we can set up a system of equations to solve for R and O:

R/O = 7/4
R = O + 150
To eliminate R, we can use the second equation:

R = O + 150

Now, substitute this expression for R into the first equation:

(O + 150)/O = 7/4

Cross-multiply to solve for O:

4(O + 150) = 7O

4O + 600 = 7O

Subtract 4O from both sides:

600 = 3O

Now, divide by 3:

O = 600/3 O = 200

Now that we know the number of owned residences (O), we can find the number of rented residences (R) using the second equation:

R = O + 150 R = 200 + 150 R = 350

So, there are 200 owned residences and 350 rented residences in the town. To find the total number of residences, simply add these two numbers together:

Total = Owned + Rented Total = 200 + 350 Total = 550

Therefore, the total number of residences in the town is 550.

বাংলাদেশ সিকিউরিটিজ অ্যান্ড এক্সচেঞ্জ কমিশন(সহকারী পরিচালক) 19-06-2021

A. 5 : 2
B. 5 : 3
C. 7 : 5
D. None

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Answer: Option A

Explanation:

1554 . A 60 litre mixture of sugar and water contains sugar adn water in the ratio 2 : 3 . How many litres of the mixture should be replaced by sugar so that the ratio of sugar and water becomes 1 : 1?

A. 6
B. 10
C. 15
D. None

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Answer: Option B

Explanation:

গ্যাস ট্রান্সমিশন কোম্পানি লিমিটেড | সহকারী ব্যবস্থাপক | ২০.০৪.২০১৮

A. -30.0377
B. -29.0377
C. -32.8246
D. -31.0377

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Answer: Option A

Explanation:

1556 . If a pen is sold at taka 55 it makes a profit of 10%. What is its purchase cost?

A. 50
B. 110
C. 45
D. 60

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Answer: Option A

Explanation:

Purchase cost of pen = (55*100)/110

= 50 tk (Ans)

পল্লী বিদ্যুতায়ন বোর্ড। এসিস্ট্যান্ট এনফোর্সমেন্ট কোঅডিনেটর। 31-12-2021

A. 3
B. 2
C. 4
D. 5

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Answer: Option A

Explanation:

বাংলাদেশ পেট্রোলিয়াম ইনস্টিটিউট (সহকারী পরিচালক) 18-12-2020

A. 14
B. 18
C. 22
D. 26

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Answer: Option A

Explanation:

বাংলাদেশ পেট্রোলিয়াম ইনস্টিটিউট (সহকারী পরিচালক) 18-12-2020

A. 0.16
B. 0.1633
C. 0.1667
D. 0.166

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Answer: Option C

Explanation:

বাংলাদেশ সিকিউরিটিজ অ্যান্ড এক্সচেঞ্জ কমিশন(সহকারী পরিচালক) 19-06-2021

A. 540
B. 600
C. 660
D. 720

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Answer: Option B

Explanation:

Let's use algebra to solve this problem.

Let A be the number of apple seeds and O be the number of orange seeds that Sue planted.

According to the given information:

1. A = 4O (Sue planted 4 times as many apple seeds as orange seeds).
2. 15% of the apple seeds grew into trees, so 0.15A apple trees grew.
3. 10% of the orange seeds grew into trees, so 0.10O orange trees grew.
4. The total number of trees is 420: A + O = 420.

Now, we can set up a system of equations based on the above information:

From equation 1, we have: A = 4O

From equations 2 and 3, we know the total number of trees: 0.15A + 0.10O = 420

Now, substitute the value of A from equation 1 into equation 2: 0.15(4O) + 0.10O = 420

Simplify the equation: 0.60O + 0.10O = 420

Combine like terms: 0.70O = 420

Now, solve for O (the number of orange seeds): O = 420 / 0.70 O = 600

So, Sue planted 600 orange seeds.

বাংলাদেশ সিকিউরিটিজ অ্যান্ড এক্সচেঞ্জ কমিশন(সহকারী পরিচালক) 19-06-2021

1546 . ৯১, ১০১, ১১৭ এবং ১২৩ এর মধ্যে মৌলিক সংখ্যা কোনটি?

1547 . রোমান সংখ্যা MCCLXXIV এর মান কত?

1548 . After decreasing 24% in the price of an article the discounted price becomes $912. Find the actual price of the article?

1549 . If K is an integer, what is the smaller: possible value of k such that 1040 is the square of an integer?

1550 . What is 3% of 0.07?

1551 . (-3, 4) বিন্দুটি কোন চতুর্থভাগে অবস্থিত?

1552 . In a certain town, the ratio of the number of rented residences to the number of owned residences is 7 : 4. Those are the only two kinds of residences in this town. If there are 150 more rented than owned residences in this town, what is the total number of residences in the town?

1553 . Price of 2 pencils is less than 20% of price of a pen. What is the ratio of the price a pen to that of a pencil?

1554 . A 60 litre mixture of sugar and water contains sugar adn water in the ratio 2 : 3 . How many litres of the mixture should be replaced by sugar so that the ratio of sugar and water becomes 1 : 1?

1555 . 0.9623 - 31 = কত?

1556 . If a pen is sold at taka 55 it makes a profit of 10%. What is its purchase cost?

1557 . The average of several exam scores is 80. One make-up exam was given. Included with the other scores, the new average was 84. If the score on the make up exam was 92, how many total exams were give?

1558 . In the coordinate plane, line m passes through the origin and has a slope of 3. If points (6,y) and (x,12) are on line m, then y - x = ?

1559 . If y exceeds x by 20%, then x is less than y by:

1560 . Sue planted 4 times as many apple seeds as she planted orange seeds. 15% of the apple seeds grew into trees, and 10% of the orange seeds grew into trees. If a total of 420 apple trees and orange trees grew from the seeds, how many orange seeds did Sue plant?

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