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1 . A student first reduced a number by 20 percent and then increased it again by 20 percent. If the difference between the two new numbers was 8, then what is the original number?

A. 40
B. 50
C. 75
D. 100

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Answer: Option B

Explanation:

Suppose, Total marks = 100

20% reduced = 80

Then, 20% increased = 80 + 80 of 20% = 96

Difference = 100 - 96 = 4

4 difference then orginal number = 100

8 difference then orginal number = (100×8)/4

= 200

20% increased = 96%

Difference between two new number= 96-80 = 16

Difference is 16 when the original number is 100

,, ,, 8 ,, ,, = 50

Answer : 50

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