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1 . The preduct of two consecutive negative ever integers is 24. What is the larger number ?

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Answer: Option A

Explanation:

Let two consecutive negetive even numbers -2n and - 2(n+1)

According to to the question we can write that,

(-2n)×{-2(n+1)}=24

Or, - 2n(-2n-2)=24

Or, 4n^2+4n=24

Or, 4(n^2+n)=24

Or, n^2+n=24/4

Or, n^2+n=6

Or, n^2+n-6=0

Or, n^2+3n-2n-6=0

Or, n(n+3)-2(n+3)=0

Or,(n+3)=0 or, (n-2)=0

Or, n=-3 [which is not acceptable]

And n=2

Then, As the first negative even integer is -2n= -2×2= -4

And -2(n+1)=-6

Larger number is - 4 between them.