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1 . Three boys have marbles in the ratio of 19: 5: 3 If the boy with the least number has 9 marbles, how many marbles does the boy with the greatest number have?

A. 57
B. 33
C. 27
D. 81

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Answer: Option A

Explanation:

Let's call the number of marbles each boy has as follows:

Boy A has 19x marbles. Boy B has 5x marbles. Boy C has 3x marbles.

We are given that Boy C has the least number of marbles, which is 9. So, we can set up the equation:

3x = 9

Now, let's solve for x:

3x = 9 x = 9 / 3 x = 3

Now that we know the value of x, we can find the number of marbles Boy A has:

Boy A has 19x = 19 * 3 = 57 marbles.

So, the boy with the greatest number of marbles is Boy A, and he has 57 marbles.

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