676 . ০.১% কে দশমিকে প্রকাশ করুন।

A. 0.01
B. 0.001
C. 0.1
D. কোনোটিই নয়

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Answer: Option B

Explanation:

0.1 % = \frac{0.1}{100} = 0.001

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কারিগরি শিক্ষা অধিদপ্তর (ইঞ্জিনিয়ারিং কলেজ এর ক্যাশ সরকার/অফিস সহায়ক) 20-08-2021

A. 6
B. 12
C. 11
D. 17

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Answer: Option C

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কারিগরি শিক্ষা অধিদপ্তর (ইঞ্জিনিয়ারিং কলেজ এর ক্যাশ সরকার/অফিস সহায়ক) 20-08-2021

A. 10
B. 12.5
C. 15
D. 20

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Answer: Option D

Explanation:

ধরি, 16 টি কলার বিক্রয়মূল্য x টাকা ∴ 1 " " " \frac{x}{16} " ∴ 4 " " " \frac{4 x}{16} " ∴ ক্রয়মূল্য=x+ \frac{4 x}{16} = \frac{20 x}{16} = \frac{5 x}{4} টাকা ∴ শতকরা লোকসান= \frac{4 x}{16} × \frac{4}{5 x} ×100=20%

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কারিগরি শিক্ষা অধিদপ্তর (হিসাব সহকারী/অফিস সহকারী কাম কম্পিউটার অপারেটর) 20-08-2021

A. ১১২৫
B. ১৩৫০
C. ১২০০
D. ২৪০০

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Answer: Option C

Explanation:

we know that,

I = pnr

=2000 ×5×12/100

=1200

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জীবন বীমা কর্পোরেশন (অফিস সহকারী কাম কম্পিউটার মুদ্রাক্ষরিক) 03-09-2021

A. ১২৩ : ২৬
B. ১৩ : ৩
C. ১৫ : ২৪
D. ১১৩ : ১৩

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Answer: Option D

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জীবন বীমা কর্পোরেশন (অফিস সহকারী কাম কম্পিউটার মুদ্রাক্ষরিক) 03-09-2021

A. 23
B. 24
C. 25
D. None

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Answer: Option A

Explanation:

মনেকরি,
টিমের সদস্যদের বয়সের গড় x বছর
.: অধিনায়ক ও উইকেট রক্ষক বাদে অন্য 9
জনের গড় = (x - 1) বছর
দেওয়া আছে,
অধিনায়কের বয়স = 26 বছর
.:. উইকেট রক্ষকের বয়স = 26 + 3 = 29 বছর
প্রশ্নমতে,
9 (x - 1) + 26 + 29 = 11x ⇒ 9 x - 9 + 26 + 29 = 11x
⇒ x = 23

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তিতাস গ্যাস ট্রান্সমিশন অ্যান্ড ডিস্ট্রিবিউসন কো. লি.-সহকারী ব্যবস্থাপক-08-10-2021

A. 120
B. 132
C. 145
D. 200

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Answer: Option A

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A. 10
B. 12
C. 14
D. 16

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Answer: Option D

Explanation:

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A. 1440
B. 1800
C. 3600
D. None

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Answer: Option B

Explanation:

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A. 1950
B. 1560
C. 1840
D. 1680

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Answer: Option D

Explanation:

মনেকরি,
নির্ধারিত সর্বনিম্ন চার্জের পরিমাণ = x টাকা
এবং প্রতি ইউনিট বিদ্যুতের দাম = y টাকা
প্রশ্নমতে,
540y + x = 1800.......... (i)
620y + x = 2040.......... (ii)
(i) - (ii)⇒
- 80y = - 240
⇒ y = 3

.: (i) ⇒
540 x3 + x = 1800
⇒1620 + x = 1800
⇒ x = 1800 - 1620
⇒ x = 180
.: 500 ইউনিটের জন্য মোট খরচ
= 180 + (500 × 3)
= 180 + 1500 = 1680 টাকা

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A. 30
B. 70
C. 100
D. 250

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Answer: Option B

Explanation:

\cos t = 100 p r o f i t = 320 % o f 100 = 320 s e l l i n g p r i c e = 100 + 320 = 420 N e w \cos t = 100 + (25 % o f 100) = 100 + 25 = 125 N e w p r o f i t = 420 - 125 = 295 N e w p r o f i t p e r c e n t e g = (\frac{295}{420} \times 100 %) = 70.23 % = 70 %

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A. 35
B. 40
C. 50
D. None

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Answer: Option B

Explanation:

Let's denote the present ages of the husband, wife, and child as H, W, and C, respectively.

According to the given information:

Four years ago, the average age of the husband, wife, and child was 27 years. So, (H - 4 + W - 4 + C - 4) / 3 = 27.

Five years ago, the average age of the wife and child was 20 years. So, (W - 5 + C - 5) / 2 = 20.

We can simplify these equations:

1. (H + W + C - 12) / 3 = 27.

2. (W + C - 10) / 2 = 20.

Now, let's solve this system of equations:

From equation 2, we can express W + C as 2 * 20 + 10 = 50.

Substitute this value into equation 1:

(H + 50 - 12) / 3 = 27.

H + 38 = 81.

H = 81 - 38.

H = 43.

So, the present age of the husband is 43 years.

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A. 2
B. 2.5
C. 3
D. None

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Answer: Option C

Explanation:

মনেকরি,
60 মাইল বেগে x ঘণ্টা যায়
.: 80 মাইল বেগে (5 - x) ঘণ্টা যায়
প্রশ্নমতে,
60x + 80(5 - x) = 340
⇒ 60x + 400 - 80x = 340
⇒ - 20x = - 60
⇒x = 3

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A. 23
B. 24
C. 25
D. 26

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Answer: Option B

Explanation:

মনে করি বেশি পরিমাণের ফলে এর মূল্য x টাকা দেওয়া আছে, কম পরিমানঃ বেশি পরিমান=2:3 অনুপাতদ্বয়ের যোগফল=2+3=5 তাহলে, 5 কেজি এর ক্রয়মূল্য=14×2+x×3=28+3x এবং 5 কেজি এর বিক্রয়মুল্য=22×5=110 ∴ লাভ=110- (28+3 x) = 110 - 28 - 3 x = 82 - 3 x প্রশ্নমতে, \frac{82 - 3 x}{28 + 3 x} ×100%=10% [10 % লাভ] \Rightarrow \frac{82 - 3 x}{28 + 3 x} = \frac{10}{100} \Rightarrow \frac{82 - 3 x}{28 + 3 x} = \frac{1}{10} \Rightarrow 820 - 30 x = 28 + 3 x \Rightarrow - 33 x = - 792 x = 24

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A. 10
B. 20
C. 40
D. 73

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Answer: Option C

Explanation:

নম্বর বেশি=83-63=20 প্রশ্নমতে, 0.5 অংশ বৃদ্ধি =20 1 অংশ বৃদ্ধি = \frac{20}{0.5} =40 ছাত্র= ছাত্রীর সংখ্যা=40

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676 . ০.১% কে দশমিকে প্রকাশ করুন।

677 . অর্নি ও তার জমজ দুইবোনের বয়সের সমষ্টি ২৩ বছর। জমজ বোনদের প্রত্যেকের বয়স ৬ বছর হলে অর্নির বয়স কত?

679 . বার্ষিক শতকরা মুনাফার হার ১২ টাকা হলে ২০০০ টাকার ৫ বছরের মুনাফা কত?

680 . পিতা ও পুত্রের বয়সের সমষ্টি ৬০ বছর এবং তাদের বয়সের অনুপাত ৭ : ২ । ৯ বছর পূর্বে তাদের বয়সের অনুপাত কত ছিল?

681 . The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older than him. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?

682 . X.Y and Z share Tk 1800 in such a way that X has 2.5 times as much as Y, and Y has has 4 times as much as Z. How much money (in Taka) does Z receive?

683 . A man travelled a distance of 61 kn in 9 jours. He travelled party on food at 4 kn/hr and party on bicycle at 9 km/hr. What is the distance (in km) travelled on foot?

684 . In a market suvey 20% respondents opted for product A whereas 60% opted for product B. the remaining individuals were not certain. If the difference in number between those who opted for product B and those who were uncertain was 720 . How many individuals were covered in the survey?

686 . In a certain store, the profit is 320% of the cost, If the cost increases by 25% but the selling price remains constant approximately what percentage of the selling prices is the profit?

687 . The average age of husband wife and their child 4 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:

688 . Jamal covered a distance of 340 miles between ciry A and B taking a total of 5 hours. If part of the distance was covered at 60 miles per hours speed and the balance at 80 miles per hour speed, how many hours didhe travel at 60 miles per hour?

689 . By mixing two qualities of pulses in the ration 2:3 and selling the mixture at the rate of Tk. 22 per kilogram, a shopkeepers makes a profit of 10%. If the cost of the smaller quantity be TK. 14 per kg the cost in Tk per kg of the larger quantity is:

690 . A student's marks were wrongly entered as 83 instead of 63. Due to the error the average marks for the class got increased by 0.5. Find the number of students in the class.

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