6721 . tan(3A)= √ 3 হলে, A=কত?

A. 45°
B. 30°
C. 20°
D. 15°

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Answer: Option C

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জাতীয় নিরাপত্তা গোয়েন্দা সংস্থা (কম্পিউটার অপারেটর) 03-04-2021

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6722 . tan(3A)= $\sqrt{3}$ হলে, A=কত?

A. $45 °$
B. $30 °$
C. $20 °$
D. $15 °$

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Answer: Option C

Explanation:

\tan (3 A) = \sqrt{3} = \tan (3 A) = \tan 60 ° = 3 A = 60 ° A = \frac{60 °}{3} = 20 °

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6723 . tahmid is four times as old as koushik.in x years,tahmid will be three times as old as koushik.how old is koushik in terms of x ?

A. 2x
B. 3x
C. 4x
D. 8x

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Answer: Option A

Explanation:

Let's use algebra to solve this problem. Let K represent Koushik's current age, and T represent Tahmid's current age. We'll set up equations based on the given information. "Tahmid is four times as old as Koushik": T = 4K "In x years, Tahmid will be three times as old as Koushik": In x years, Tahmid's age will be T + x, and Koushik's age will be K + x. So, we can write: T + x = 3(K + x) Now, we have a system of two equations: T = 4K T + x = 3(K + x) We can solve this system of equations to find Koushik's age (K) in terms of x. First, substitute the value of T from the first equation into the second equation: 4K + x = 3(K + x) Now, let's solve for K: 4K + x = 3K + 3x Subtract 3K and x from both sides: 4K - 3K = 3x - x K = 2x So, Koushik's current age, in terms of x, is 2x.

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BCSIC নিয়োগ পরীক্ষা - ২০১৮ পদ: এক্সটেনশন অফিসার তারিখ: ০৯-১১-২০১৮

A. 2/3 Kt
B. 3/2KT²
C. 3/2 KT

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Answer: Option A

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ক ইউনিট (2010-2011) || ঢাকা বিশ্ববিদ্যালয় || 2010

A. 2 : 1
B. 1 : 2
C. 1 : 1
D. 3 : 1

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Answer: Option C

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বাংলাদেশ সেতু কর্তৃপক্ষ (সহকারী সাব-ইঞ্জিনিয়ার) 18-12-2020

A. 151
B. 135
C. 141
D. 138
E. None

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Answer: Option B

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সাধারণ বীমা কর্পোরেশন || সহকারী ব্যবস্থাপক (08-11-2024) || 2024

A. 540
B. 600
C. 660
D. 720

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Answer: Option B

Explanation:

Let's use algebra to solve this problem.

Let A be the number of apple seeds and O be the number of orange seeds that Sue planted.

According to the given information:

1. A = 4O (Sue planted 4 times as many apple seeds as orange seeds).
2. 15% of the apple seeds grew into trees, so 0.15A apple trees grew.
3. 10% of the orange seeds grew into trees, so 0.10O orange trees grew.
4. The total number of trees is 420: A + O = 420.

Now, we can set up a system of equations based on the above information:

From equation 1, we have: A = 4O

From equations 2 and 3, we know the total number of trees: 0.15A + 0.10O = 420

Now, substitute the value of A from equation 1 into equation 2: 0.15(4O) + 0.10O = 420

Simplify the equation: 0.60O + 0.10O = 420

Combine like terms: 0.70O = 420

Now, solve for O (the number of orange seeds): O = 420 / 0.70 O = 600

So, Sue planted 600 orange seeds.

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বাংলাদেশ সিকিউরিটিজ অ্যান্ড এক্সচেঞ্জ কমিশন(সহকারী পরিচালক) 19-06-2021

A. 30%
B. 32%
C. 34%
D. 35%

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Answer: Option B

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২৯ তম বিসিএস প্রিলিমিনারি টেস্ট (14-08-2009)

6729 . Solve for $x$ if $16 x - 4 = 68 + 7 x$

A. $x = 16$
B. $x = - 16$
C. $x = 8$
D. $x = 5$

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Answer: Option C

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বাংলাদেশ অর্থনৈতিক অঞ্চল কর্তৃপক্ষ (BEZA) | সহকারী ব্যবস্থাপক | ৩০.১১.২০১৮

6730 . Solve for the value of x and y : $3^{x} = 9^{y}, 5^{x + y + 1} = 25^{x y}$

A. (0,-1), 11/23
B. (2,1), $(\frac{- 1}{2} \frac{- 1}{4})$
C. (1/2 1/3), (-2,-1)
D. (2,1), $(\frac{- 1}{4} \frac{1}{2})$

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Answer: Option B

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6731 . Solution X contains 40% salt and 60% water by weights, Solution Y contains 25% salt and 75% water. If a mixture of X and Y contains 30% salt. What percent of the weight of this mixture is solution X?

A. 10%
B. 33.3%
C. 40%
D. 42.5%

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Answer: Option B

Explanation:

Let x g be the weight of solution X in 100 g of the mixture.
Then, the weight of solution Y in 100 g of the mixture = (100 - x) g

Mass of salt in the mixture:
x (40%) + (100 - x) (25%) = 100 (30%)
40x + 2500 - 25x = 3000
15x = 500
x = 33 1/3

Hence, there are (33 1/3)% of solution X in the mixture.

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তিতাস গ্যাস ট্রান্সমিশন অ্যান্ড ডিস্ট্রিবিউসন কো. লি.-সহকারী ব্যবস্থাপক-08-10-2021

6732 . sinA + cosA = sinB + cosB হলে , A + B = ?

A. π
B. 2π
C. $\frac{π}{2}$
D. $\frac{π}{4}$

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Answer: Option C

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বাংলাদেশ টেলিযোগাযোগ নিয়ন্ত্রণ কমিশন (উপ-সহকারী পরিচালক) 19-02-2021

A. -1
B. 1
C. 1/2
D. 1 √ 2

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Answer: Option B

Explanation:

\sin^{2} 21 ° + \sin^{2} 69 ° = \sin^{2} (21 ° + 69 °) = \sin^{2} 90 ° = 1

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৮ম বেসরকারি প্রভাষক নিবন্ধন পরীক্ষা (01-09-2012)

A. ০
B. ১
C. -১
D. ৯০

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Answer: Option C

Explanation:

sinθ ও cosθ - এর সর্বোচ্চ ও সর্বনিম্ন মান যথাক্রমে + 1 - 1 সুতরাং - sinθ - এর সর্বনিম্ন মান - 1 ।

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সংসদ সচিবালয় ।। ব্যাক্তিগত কর্মকর্তা (নন ক্যাডার) (15-05-2023)

A. 0 °
B. 30 °
C. 45 °
D. 90 °

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Answer: Option C

Explanation:

Sinθ= cosθ বা, Sinθ/ cosθ= cosθ/ cosθ [উভয় পক্ষকে cos দ্বারা ভাগ করে] বা, tanθ=1 বা, θ= 45° Ans

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সরকারি মাধ্যমিক বিদ্যালয় সহকারী শিক্ষক নিয়োগ পরীক্ষা-2001-(20-05-2001)

6721 . tan(3A)= √ 3 হলে, A=কত?

BdMerit-এর ১ বছরের প্রিমিয়াম প্যাকেজ কিনে ১০ মাস নিয়মিত প্রস্তুতি নিন—

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6723 . tahmid is four times as old as koushik.in x years,tahmid will be three times as old as koushik.how old is koushik in terms of x ?

6724 . T তাপমাত্রায় আদর্শ গ্যাসের ক্ষেত্রে একটি অণুর গড় গতি শক্তি -

6725 . Sumon bought 2 varieties of rice, costing Taka 8 per kg and Taka 12 per kg each and mixed them in some ratio. Then he sold the mixture at Taka 12 per kg, making a profit 20%. What has the ratio of mixture?

6726 . Sum of three consecutive multiples of 3 is 396. Find the largest number.

6727 . Sue planted 4 times as many apple seeds as she planted orange seeds. 15% of the apple seeds grew into trees, and 10% of the orange seeds grew into trees. If a total of 420 apple trees and orange trees grew from the seeds, how many orange seeds did Sue plant?

6728 . Successive discount of 20% and 15% are equal to a single discount of--

6731 . Solution X contains 40% salt and 60% water by weights, Solution Y contains 25% salt and 75% water. If a mixture of X and Y contains 30% salt. What percent of the weight of this mixture is solution X?

6733 . sin221°+sin269°=কত?

6734 . Sin θ এর সর্বনিম্ন মান কত?

6735 . sin θ = cos θ হলে θ এর মান কত?

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